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log2 9×log3 2怎么算?

log2(9)=log2(3²)=2log2(3) ∴log2(9)×log3(2)=2log2(3)×log3(2) =2×1 =2 望采纳

是×还是比大小 ×的话:原式=(lg25/lg2)×(lg4/lg3)×(lg9/lg5) =(2lg5/lg2)×(2lg2/lg3)×(2lg3/lg5) =8 比大小的话:log2 16

解 log2(9)×log3(8) =log2(3²)×log3(2³) =2log2(3)×3log3(2) =6×log2(3)×log3(2) =6×1 =6

原式=(lg9/lg2)x(lg4/lg3)=(2lg3/lg2)x(2lg2/lg3)=4

log2(log3(x))=1 log3(x)=2 x=9

解析 可以这么来做 log3 9^(-1) =-log3 9 =-2 希望对你有帮助 学习进步O(∩_∩)O谢谢

都换成以2为底的对数进行比较 log2(3)=log2(根号9) log4(5)=log2(根号5) 3/2=log2(2^(3/2))=log2(根号8) 因为y=log2(x)在(0,+无穷)上为增函数 所以log2(3)>3/2>log4(5)

log2 4+log3 9=2+2=4.

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